In a seminar, number or participants in physics, chemistry, maths are 48, 60, 96. Find number of rooms required if in each room, the same number of participants is to be seated and all of being of a same subject
Answers
Answered by
5
Hey!!!!
Basically, rooms required = HCF(48,60,96)
Thus by Prime Factorisation Method
=> 48 = 2⁴ x 3
=> 60 = 2² x 3 x 5
=> 96 = 2^5 x 3
Thus HCF(48,60,96) = 2² x 3
=> HCF = 12
Thus 12 rooms will be required.
Hope this helps
Basically, rooms required = HCF(48,60,96)
Thus by Prime Factorisation Method
=> 48 = 2⁴ x 3
=> 60 = 2² x 3 x 5
=> 96 = 2^5 x 3
Thus HCF(48,60,96) = 2² x 3
=> HCF = 12
Thus 12 rooms will be required.
Hope this helps
Answered by
3
Hey Mate!
~~~~~~~~
Here is your answer :
==============================
Given,
Number of participants in physics = 48
Numbers of Participants in Chemistry = 60
Number of participants in Maths = 96
HCF of 48,60,96
From prime Factorization,
48 = 2 × 2 × 2 × 2 × 3
60 = 2 × 2 × 3 × 5
96 = 2 × 2× 2 × 2 × 2 × 3
HCF = 2 × 2× 3 = 12
HOPE THIS HELPS U...
~~~~~~~~
Here is your answer :
==============================
Given,
Number of participants in physics = 48
Numbers of Participants in Chemistry = 60
Number of participants in Maths = 96
HCF of 48,60,96
From prime Factorization,
48 = 2 × 2 × 2 × 2 × 3
60 = 2 × 2 × 3 × 5
96 = 2 × 2× 2 × 2 × 2 × 3
HCF = 2 × 2× 3 = 12
HOPE THIS HELPS U...
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