In a seminar the number of participants in Hindi, English and Mathematics are 60,84 and 108 respectively. Find the minimum number of rooms required if in each room the same number of participants are to be seated and all of them being in the same subject What value is depicted?
Answers
The no. of students seated in each room would be H.C.F of all the three values above.
60 =2×2×3×5
84=2×2×3×7
108=2×2×3×3×3
Therefore hcf = 12
Now no. of rooms required are total number of students divided by no. of students in each room.
* No of rooms= 60+84+108/12
=21
Answer:
21 rooms needed
Step-by-step explanation:
In this question, we are required to find the greatest common divisor.
2. 60. 84. 108
2 30. 42. 54
3. 15. 21. 27
5. 7. 9
Reaching here, we will stop the division, because we cannot find a common divisor for 5, 7, and 9. Therefore, the GCD is 2×2×3 = 12
Hence, we have found our common divisor to be 12, we therefore are going to divide this by the number of the students, to get how many rooms are needed.
The total number of students is
84 + 60 + 108 =252.
Since we have seen that only 12 students are required for each room, equally, we will divide the total number of students by 12
252 ÷ 12 = 21
Hence 21 rooms are needed.