Question

In a seminar the number of participants in Mathematics, Physics and Biology are 336, 240 and 96. Find the minimum number of rooms required if in each room same number of participants is to be seated and all of them being in the same subject

Answer 1

since same no. of participants is required in each room ,we need to.calculate the HCF(336,240,96)=48
so total rooms will be 336/48 +240/48 +96/2=14 rooms they are minimum.possible rooms if all rooms have same no. of students

Answer 2

The minimum number of rooms required for each room contains same number of participants is to be seated is 14.

H.C.F

H.C.F is the highest common multiple. It refers to highest common prime factor by which given number can be divided.

Given:

The number of participants in Mathematics is 336.

The number of participants in Physics is 240.

The number of participants in Biology is 96.

Explanation:

As same numbers of participants are required to be in each room.

calculate the HCF (336,240,96) = 48.

Total rooms for mathematics  is  $\frac{336}{48} =7$.

Total rooms for physics is $\frac{240}{48} =5$.

Total rooms for biology is $\frac{96}{48} =2$.

For total room $7+5+2=14$

Therefore, total number of rooms needed is 14.

To know more about how to find and H.C.F, here

https://brainly.in/question/16593892?msp_poc_exp=2

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