Question

In a series L-R circuit, XL = R and power factor of the circuit is P1 When a capacitor with capacitance C such that XL = Xc is put in series, the power factor becomes P2 Find P1/P2

Answer 1

Answer:

p1÷p2=1÷√2

Explanation:

in first circuit only inducter and resistance is present and the this resultant of the voltage will be 45 degrees ahead of current.

and in second one capacitor also involved and given XL=Xc them the resultant resistence/voltage in the direction of current and the angle is 0 degrees.

p1 power factor is cos(45)=1÷√2

p2 power factor is cos(0)=1.

so p1÷p2 is 1÷√2