Physics, asked by work24, 3 months ago

In a series LCR circuit in which R=3 ohm ,L=25 mH
and C = 800 uF a sinusoidal a.c voltage of peak
value 250 V is applied. Find
(1) frequency at which resonance occurs
(ü) current in the circuit at resonant condition.​

Answers

Answered by ғɪɴɴвαłσℜ
25

\sf{\huge{\underline{\orange{Given :-}}}}

  • A series LCR circuit in which R=3 ohm ,L=25 mH and C = 800 uF a sinusoidal a.c voltage of peak value 250 V is applied.

\sf{\huge{\underline{To\:Find :-}}}

  • Frequency at which resonance occurs.

  • Current in the circuit at resonant condition.

\sf{\huge{\underline{\green{Answer :-}}}}

A circuit containing LCR, L = indicator, C = Capacitor, R = Resistor

It is connected to AC supply.

  • R=3 ohm

  • L=25 mH = 25 ×  {10}^{ - 3}

  • C = 800 uF = 800 ×  {10}^{ - 6}

  • Peak value 250 V

a.) Frequency at which resonance occurs.

➝ Resonant frequency =

\large{f} =  \frac{1}{2\pi \sqrt{LC} }

\large{f} =  \frac{1}{2\pi \sqrt{LC} }

➝ f = 1/2π× 25 ×  {10}^{ - 3} × 800 ×  {10}^{ - 6}

➝1/ 20000 ×  {10}^{ - 9}

➝1/ 2 ×  {10}^{ - 9-4}

➝ 1/2 ×  {10}^{ - 11}

\large{f} =  \frac{1}{2 \times 2 \times {10}^{ - 11}}

➝ 2.5 ×  {10}^{10} rad s-¹

b.) Current in the circuit at resonant condition

➝ I =  {V}\times{ R}

➝ I =  {250}\times{ 3}

I = 83.34 A

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