In a series LCR circuit with an AC source, R = 300 Ω, C = 20 μF, L = 1.0 henry, εrms = 50 V and ν = 50/π Hz. Find (a) the rms current in the circuit and (b) the rms potential difference across the capacitor, the resistor and the inductor. Note that the sum of the rms potential differences across the three elements is greater than the rms voltage of the source.
Answers
(a) The rms current in the circuit is
(b) The rms potential difference across the capacitor, the resistor and the inductor is 90 V
Explanation:
Resistance in LCR circuit sequence, R = 300 Ω
Potential on LCR series circuit, C = 20 μF= 20 × 10−6 F
Inductance in LCR circuit series, L = 1 Henry
RMS Voltage Value, εrms = 50 V
Source Frequency, f =50/π Hz
The inducer reactance (XL) is given by,
= 100 Ω
Capacitance Reactance () is given through,
(a) The rms current in the circuit :
Impedance of an LCR (Z) circuit is provided by,
The current RMS value (Irms) shall be given by,
(b) The rms potential difference across the capacitor, the resistor and the inductor:
The condenser potential () is given by,
Potential resistor difference () is given by,
Potential inducer difference () is given by,
R.M.S potential = 50 V
Total sum of all potential falls = 50 V + 30 V + 10 V = 90 V
Total potential falls > use of RMS potential
Answer:
Answer is here by attached .hope you understand
Explanation: