Question

In a series RLC circuit the rms voltage across the resistor and the inductor are respectively 400v and 700v .If the equation for the applied voltage is e=500√2sinwt then the peak voltage across the capacitor is ?

Answer 1

The peak voltage across the capacitor is Eo = 400 √2

Explanation:

Given data:

E = 500 √ 2 sinωt

E(rms )  =  2 Eo / √ 2

           =  500√  2/ √ 2 = 500 V

E(rms) ^2  = =E^2 R   +(EL  −E C )^ 2

250000 = 10000 + (700−E C )^2

(700−EC )^2 = 90000

700− Ec √ 90000

E  c  =700-300

Ec = 400

E(rms)C = Eo / √2

Eo = √2 E(rms)C

     =  √2 x 400

Eo = 400 √2

Hence the peak voltage across the capacitor is Eo = 400 √2

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