In a simultaneous throw of a pair of dice, find the probability of getting a sum of at most 5.
Answers
Answered by
0
Total possible outcomes are 14,23,32,41
Probability = favourable outcomes/total outcomes
= 4/36
= 1/9
therefore probability = 1/9
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Answered by
0
the outcomes are
(1,1);(1,2);(1,3);(1,4);(1,5);(1,6)
(2,1);(2,2);(2,3);(2,4);(2,5);(2,6)
(3,1)...........
the total outcomes are 36
the favorable outcomes are (1,4);(2,3);(3,2);(4,1)
4/36=1/9
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