in a simultaneous throw of a pair of dice find the probability of getting an even number on first
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Answer:
Step-by-step explanation:
we throw a pair of dice, so we have 6 possible outcomes on the first and 6 on the second
so, total we have 6 x 6 = 36 outcomes,
now
with even outcome on first we have cases as
CASE 1) with 2 on dice 1= 6 cases as from 2,1 ....... to 2,6
CASE 2) with 4 on dice 1= 6 cases as from 4,1 ....... to 4,6
CASE 3) with 6 on dice 1= 6 cases as from 6,1 ....... to 2,6
total favorable outcomes = 6 + 6 + 6 = 18
probability = favorable / total = 18/36 = 1/2
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