Question

in a simultaneous throw of a pair of dice, find the probability of getting an even number on one and a multiple of 3 on the other

Answer 1

on 1= 1by2
on2=2by2
hope you will understand my cocept
and what i want to say you.

Answer 2

Answer: Our required probability is $\frac{1}{6}$

Step-by-step explanation:

Since we have given that

Number of dice we have = 2

Possible outcomes of getting an even number of one and a multiple of 3 on the other is given by

$\{(2,3),(2,6),(4,3),(4,6),(6,6),(6,3)\}$

Total number of outcomes = 36

So,  Probability of getting an even number on one and a multiple of 3 on the other is given by

$\frac{\text{ Number of favourable outcome}}{\text{ Total number of outcomes}}\\\\=\frac{6}{36}\\\\=\frac{1}{6}$

Hence, Our required probability is $\frac{1}{6}$