Math, asked by gsbraich76, 1 year ago

in a simultaneous throw of a pair of dice, find the probability of getting an even number on one and a multiple of 3 on the other

Answers

Answered by satyajitkr
10
on 1= 1by2
on2=2by2
hope you will understand my cocept
and what i want to say you.
Answered by RenatoMattice
14

Answer: Our required probability is \frac{1}{6}

Step-by-step explanation:

Since we have given that

Number of dice we have = 2

Possible outcomes of getting an even number of one and a multiple of 3 on the other is given by

\{(2,3),(2,6),(4,3),(4,6),(6,6),(6,3)\}

Total number of outcomes = 36

So,  Probability of getting an even number on one and a multiple of 3 on the other is given by

\frac{\text{ Number of favourable outcome}}{\text{ Total number of outcomes}}\\\\=\frac{6}{36}\\\\=\frac{1}{6}

Hence, Our required probability is \frac{1}{6}

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