in a simultaneous throw of a pair of dice find the probability of getting a doublet of even numbers
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when a pair of dice is thrown, the total possible
outcome is 6^2 that is 36
doublets are (1,1)....(6,6)
even doublets are (2,2) (4,4) and (6,6)
there fore probability is 3÷36 ie 1 ÷12
outcome is 6^2 that is 36
doublets are (1,1)....(6,6)
even doublets are (2,2) (4,4) and (6,6)
there fore probability is 3÷36 ie 1 ÷12
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Answer:
Step-by-step explanation:when two dice are thrown simultaneously, the total number of getting possibilities are =36.
Let A be the event of getting an even number =27
P(A)= number of getting an even number/total number of possibilities
P(A)= 27/36
P(A)=3/4
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