Question

in a simultaneous throws of two die find the probability of getting a doublet

Answer 1

 Outcomes         =  {1,1} , {1,2} , {1,3} , {1,4} , {1,5} ,{1,6} 
                          = {2,1} , {2,2} ,{2,3} , {2, 4} , {2 ,5} , {2 ,6}
                          = {3,1} , {3,2} ,{3,3} ,{3 ,4}, {3 ,5} ,{3 ,6 }
                          = {4 ,1} ,{4 ,2}, {4 ,3}, {4 ,4},{4 ,5} ,{4, 6}
                          = {5,1} ,{5,2} ,{5,3}, {5,4}, {5,5}, {5 ,6}
                          = {6 ,1} , {6 ,2} ,{6 ,3} ,{6 ,4 }, {6 ,5} ,{6 ,6}

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Total outcomes =  6 * 6 = 36 

Favorable outcomes = 6 [ {1,1},{2,2},{3,3},{4,4},{5,5}{6,6} ]



P = $\frac{6}{36} = \frac{1}{6}$


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Answer 2

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,2) (2,3) (2,4) (2,5) (2,6) (3,3) (3,4) (3,5) (3,6) (4,4) (4,5) (4,6) (5,5) (5,6) (6,6) these are the probability when 2 dies are thrown simultaneously