Question

In a single through of two dice the probabity of getting a total other than 9 or 11 is

Answer 1

Total number of outcomes=21

{1+1=2;1+2=3;1+3 =4;1+4=5;1+5=6;1+6=7}

{2+2=4;2+3=5;2+4=6;2+5=7;2+6=8}

{3+3=6;3+4=7;3+5=8;3+6=9}

{4+4=8;4+5=9;4+6=10}

{5+5=10;5+6=11}

{6+6=13}

Favourable outcomes of getting a total other than 9 or 11=18

Therefore probability of getting a total other than 9 or 11=Favourable no. of outcomes/total no. of outcomes=18/21=6/7

Hope it helps you.....