Question

in a single throw of two coin find the probability of getting both
tails ​

Answer 1

Answer:

P(both tails) = favorable outcomes/total outcomes. 1/4.

P(at least one tail) = 3/4.

P(at most one tail) = 2/4 = 1/2.

Answer 2

Answer:

Total outcomes [n(S)] = 4

Outcome of two tails [n(T)] = 1

Probability [P(T)] = n(T)/n(S)

= 1/4

Hope my answer is clear enough.

Thanks