In a single throw of two coins, find the probability of getting
both tail
atleast 1 tail
both head
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2
Answer:
Probability of getting both tails = (number of two tails occurred) / (total number of outcomes) = 41.
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POSSIBLE OUTCOMES ARE
(HHH) , (TTT) , (HTT) , (THT) , (TTH) , (THH) , (HTH) , (HHT) = 8
TWO TAILS : 4
P ( Getting atleast 2 tails ) = 4/8 = 1/2
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