Question

In a single throw of two dice , find the probability of getting a doublet of even number
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Answer 1

Total number of outcomes = 6 × 6 = 36

Favourable outcomes = (2,2) (4,4) (6,6) = 3

$p(e) = \frac{number \: of \: favourable \: outcomes \: }{total \: number \: of \: outcomes} \\ p(doublet \: of \: even \: number) = \frac{3}{36} = \frac{1}{12}$