Question

in a single throw of two different coins find the probability of getting both tails​

Answer 1

Answer:

1/4

Step-by-step explanation:

Number of coins tossed = 2.

Total outcomes n(S) = 2² = 4{H,T,T,H}

Let E be the event of getting both tails.

n(E) = 1{TT}

Required probability P(E) :

= n(E)/n(S)

= 1/4

Hope it helps!

Answer 2

Answer: 1/4

Step-by-step explanation:

Total outcome =  4 (Head-head ,Head-tail, tail-Head, tail-tail)

favorable outcome = 1 (tail-tail)

P(E) = Favorable outcome/total outcome

P(E) = 1/4