Math, asked by Adityarocks7973, 10 months ago

In a soft drink plant, machine A fills up a bottle, machine B caps it, and then machine C puts a label on it. A (bottling) -> Average rate = 3600 unit/hr, Normal distribution with std dev = 360 units/hr
B(capping) -> Average rate = 4000 unit/hr, Normal distribution with std dev = 360 units/hr
c ( labeling) -> Average rate = 3600 unit/hr, Normal distribution with std dev = 360 units/hr
Machine A gets empty bottles at the rate of 5000 unit per hour. What will be the average of the output line?
Options a) Less than 3600 units/hr
b) Exactly 3600 units/hr
c) Between 3600 units/hr and 4000 units/hr
d) Exactly 4000 units/hr
e) More than 4000 units/hr

Answers

Answered by nidaeamann
5

Answer:

a) Less than 3600 units/hr  

Step-by-step explanation:

Considering the average rates of production of each part

A (bottling) -> Average rate = 3600 unit/hr

B(capping) -> Average rate = 4000 unit/hr

c ( labeling) -> Average rate = 3600 unit/hr

Taking the HCF (highest common factor) among all the 3, since it is a batch process and machine speeds have to be synchronized;

The factors of 3600 are: 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 16, 18, 20, 24, 25, 30, 36, 40, 45, 48, 50, 60, 72, 75, 80, 90, 100, 120, 144, 150, 180, 200, 225, 240, 300, 360, 400, 450, 600, 720, 900, 1200, 1800, 3600

The factors of 4000 are: 1, 2, 4, 5, 8, 10, 16, 20, 25, 32, 40, 50, 80, 100, 125, 160, 200, 250, 400, 500, 800, 1000, 2000, 4000

Then the greatest common factor is 400

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