Question

In a solution of 7.8g benzene and 46.0g toluene the mole fraction of benzene is

Answer 1

Answer:

The mole fraction of benzene is 0.1694.

Explanation:

Mass of benzene = 7.8 g

Moles of benzene = $n_1=\frac{7.8 g}{78 g/mol}=0.1 mol$

Mass of toluene = 7.8 g

Moles of toluene = $n_2=\frac{46.0 g}{93 g/mol}=0.49 mol$

Mole fraction of benzene :

$\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.1 mol}{0.1mol+0.49 mol}=0.1694$

Mole fraction of toluene :

$\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.49 mol}{0.1mol+0.49 mol}=0.8305$

The mole fraction of benzene is 0.1694.