Question

In a solution of CuSO₄, 0.5 A current passes for 60 minutes. How much copper is deposited if current efficiency is 50%? (Cu = 63.5)
(Class XII, Chemistry, Electrochemistry)

Answer 1

Answer:

Correct option is C)

The quantity of electricity passed =Q(C)=0.5F=0.5×96500C=48250C.

Molar mass of copper = 63.5

mol

g

.

Moles of electrons passed =

96500

mole

−

C

Q(C)

=

96500

mole

−

C

48250C

=

96500

48250

mole

−

The weight of copper deposited =molarmassofCu×moleratio×molesofelectronspassed

=63.5

mol

g

×

2mole

−

1molCu

×

96500

48250

mole

−

=15.875g.