In a solution of CuSO₄, 0.5 A current passes for 60 minutes. How much copper is deposited if current efficiency is 50%? (Cu = 63.5)
(Class XII, Chemistry, Electrochemistry)
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Answer:
Correct option is C)
The quantity of electricity passed =Q(C)=0.5F=0.5×96500C=48250C.
Molar mass of copper = 63.5
mol
g
.
Moles of electrons passed =
96500
mole
−
C
Q(C)
=
96500
mole
−
C
48250C
=
96500
48250
mole
−
The weight of copper deposited =molarmassofCu×moleratio×molesofelectronspassed
=63.5
mol
g
×
2mole
−
1molCu
×
96500
48250
mole
−
=15.875g.
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