Question

in a square abcd an equilateral triangle APC is drawn and a diagonal cuts triangle at point e . ae=2 cm find area of square


tq i m from mh. ​

Answer 1

Step-by-step explanation:

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Answer 2

In a given figure,

AAP B is an equilateral triangle.

So, AP PB = AB

equilateral triangle)

(Properties of

ZPAB = ZABP = BPA = 60°.

(All angles of equilateral triangle are equal and 60°)

ZOAB = 60° - (1)

We know that all angles all square are 90°

So, ZCDA = 90° DB is a diagonal of square ABCD with bisect

ZCDA equally.

Then, CDB = 45°.

We know that AB = CD and AB // CD then, ZCDB = LABD = 45° -- (Alternate angles)

ZDBA = 45° i.e ZABO = 45° --(2)

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In AAOB,

ZAOB ZOAB+ ZABO = 180°

From (1) and (2),

ZAOB + 60° + 45° = 180°

... ZAOB = 75°