Geography, asked by namuun5640, 1 day ago

Prove that the medians drawn from the vertex of the base of an equilateral triangle are equal

Answers

Answered by XoneutrXo

Answer:

Let ABC be a triangle AH the height from A to BC and AM the median (M the midpoint between B and C) without loss of generality let's say that H is between B and M so we have ΔBAH and ΔMAH congruent as angles BHA and MHA are equal angle BAH and MAH are equal (per hypothesis of problem) and they share side AH. Therefore BM=HM(Or Hm=

= 2

= 21

= 21 BM)

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MC

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH =

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH = AC

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH = ACAH

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH = ACAH but MH=

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH = ACAH but MH= 2

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH = ACAH but MH= 21

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH = ACAH but MH= 21 MB=

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH = ACAH but MH= 21 MB= 2

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH = ACAH but MH= 21 MB= 21

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH = ACAH but MH= 21 MB= 21 MC

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH = ACAH but MH= 21 MB= 21 MCtherefore

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH = ACAH but MH= 21 MB= 21 MCtherefore MC

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH = ACAH but MH= 21 MB= 21 MCtherefore MCMH

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH = ACAH but MH= 21 MB= 21 MCtherefore MCMH =

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH = ACAH but MH= 21 MB= 21 MCtherefore MCMH = 2

= 21 BM) So, Lets' see ΔAHC. AM is bisector therefore we have ratios MCMH = ACAH but MH= 21 MB= 21 MCtherefore MCMH = 21

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