Question

In a square ABCD prove that BD^2=2AB^2

Answer 1

Answer:

WE KNOW THAT IN A SQUARE ALL SIDES ARE EQUAL

AB=BC=CD=AD

ALSO EVERY ANGLE=90

SO IN ΔABD

∠B=90

BD= HYPOTENUSE/DIAGONAL

BD²=AB²+AD²   (PYTHAGORAS THEOREM)

BD²=AB²+AB²  (ALL SIDES ARE EQUAL)

BD²=2AB²

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

as we know in pythagorus theorem, b²+p²=h²

here b=p as all sides are equal

side ab=side ad

b=side ab

p =side ad

h= bd

so let side ad and ad be x as both values are equal

x²+x²=bd²

=2x²=bd²

2ab²=bd² or 2ad²=bd²