Question

In a square land of size 40m x 40 m an area of
30 m * 20 m is to be constructed. The
remaining area is to be utilized for drying
chips etc., it is to be tiled at the rate of Rs 100
per m'. Find the cost of tiling.
​

Answer 1

Answer:

Area of squareland = 40^2 = 1600m2

Area of rectangle = 30x20 = 600m2

Remaining = 1600-600=1000m2

cost of tiling@Rs 100 per m2

1000x100 = Rs.100000

Answer 2

CORRECT QUESTION :

• In a square land of size 40m x 40 m an area of 30 m * 20 m is to be constructed. The remaining area is to be utilized for drying chips etc., it is to be tiled at the rate of Rs 100 per m^2. Find the cost of tiling.

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore Cost\:of\:tilling=1,00,000\:ruppes}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{given :}} \\ \implies \text{ dimension \: of \: square }=( 40 \times 40 ) m\\ \\ \implies \text{dimension \: of \: rectangle }= (30 \times 20)m \\ \\ \implies \text{ rate \: of \: tiling = 100 rupees per }{m}^{2} \\ \\ \red{ \underline \bold{to \: find :}} \\ \implies \text{cost \: of \: tilling \: remaining \: ground = ?}$

$\bold{for \: remaining \: field : } \\ \implies remaining \: field = area \: of \:square - area \: of \: rectangle \\ \\ \implies remaining \: field = ({side})^{2} - l \times b \\ \\ \implies remaining \: field =( {40})^{2} - 30 \times 20 \\ \\ \implies remaining \: field =1600 - 600 \\ \\ \blue{\implies \text{remaining \: field =1000 } m^{2} } \\ \\ \bold{ cost \: for \: tilling \: 100 0{m}^{2} \: ground } \\ \implies cost \: of \: tiling \: {1m}^{2} \: ground = 100 \: rupees \\ \\ \implies cost \: for \: tilling \: 100 0{m}^{2} \: ground = 100 \times 1000 \\ \\ \green{\therefore \text{cost \: for \: tilling \: 1000}{m}^{2} \text{ ground = 100000 \: rupees}}$