Question

In a square pqrs, if pq=(3x-10) and qr=(x+8) . Find the value of x and the length of each side of a square​

Answer 1

Answer:

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Step-by-step explanation:

(i) Sides of square are equal.

PQ = QR

=> 3x – 7 = x + 3

=> 3x – x = 3 + 7

=> 2x = 10

x = 5

PS = PQ = 3x – 7 = 3 x 5 – 7 = 8

(ii) PR = 5x and QS = 9x – 8

As diagonals of square are equal.

PR = QS

5x = 9x – 8

=> 5x – 9x = -8

=> -4x = -8

=> x = 2

QS = 9x – 8 = 9 x 2 – 8 =10

Answer 2

Answer:

17

Step-by-step explanation:

pqrs is a square

pq=qr=rs=sr..........................................(1)

pq=(3x-10) and qr=(x+8)

using (1)

pq=qr

3x-10=x+8

2x=18

x=9

length of side of square= x+8=17