in a square the length of diagonal is 6cm then its area is
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Answer:
First, we know the shape is a square. Squares have sides of equivalent length. Thus, we have A= x^2, where x is the length of one side.
We also know the length of the diagonal.
In order to solve we would need the Pythagorean Theorem. a^2 + b^2 = c^2. The diagonal being a hypotenuse of a triangle of equal side lengths, we have 2x^2 = 36, and thus x^2 = 18.
Since we established the square of the side length, x, is the area of the square, A = 18.
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1
Answer:
Pythagoras theorem
AB² +BC²=AC²
√6²+6²=AC
AC= 6√2 dignoal
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