In a store bags of coal powder each contained the following weights of powder (in kg): 7.97; 7.05; 7.08; 6.03; 7.00; 6.06; 6.08; 6.04; 6.00; 6.98; 7.15; 7.34; 7.23; 6.94; 7.12 kg. Find the probability that any of these bags chosen at random contains more than 7.1 kg of coal powde
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Total numbers of bags (n) => 15
Total number of bags having more than 7.1kg of coal (e) => 5 bags.
P = e/n
= 5/15
= 1/3.
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Total number of bags having more than 7.1kg of coal (e) => 5 bags.
P = e/n
= 5/15
= 1/3.
Ans.
Hope this helps....
#followme...
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