CBSE BOARD X, asked by desaiomprakash345, 25 days ago

In a straight line Subject: PHYSIC a. 6m 12. A car moving with a speed of 50km h can be stopped applying brakes after moving atleast 6m. If the same car moving at a speed of 100km h - the minimum stoppin distance is b. 12m C. 18m d. 24m 13. A bullet fired into a wooden block loses half of its velocit after penetrating 40cm. It comes to rest after penetrating a further distance of a. cm cm da

Answers

Answered by xxqueenxx01
0

Answer:

see this attachment hope it's helpful to you

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Answered by atharvpujari96
0

Given, u=50km/hr=50×

18

5

=

18

250

m/s

v=0

s=6m(at least)

By third equation by motion,

v

2

=u

2

+2as

0=(

18

250

×

18

250

)+2(−a)(s)

0=192.90−12a

a=

12

192.90

=16.07

Now applying third equation of motion,

v

2

=u

2

+2as

⟹0=(100×

18

5

)

2

+2(−16.07)(s)

⟹0=771.60−32.14s

⟹s=

32.14

771.60

=24.00

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