Question

In a study of helicopter usage and patient survival, among the 41,315 patients transported by helicopter, 298 of them left the treatment center against medical advice, and the other 41,017 did not leave against medical advice. if 60 of the subjects transported by helicopter are randomly selected without replacement, what is the probability that none of them left the treatment center against medical advice?

Answer 1

total no. if observations=41315
no. of frequency required=41017
portability=41017/41315

Answer 2

Answer: Probability that none of them left the treatment center against medical advice is 0.64.

Step-by-step explanation:

Since we have given that

Total number of patients transported by helicopter = 41315

Number of patients among them left the treatment center against medical advice = 298

Number of patients who did not leave against medical advice = 41017

Randomly they have selected 60 of the subjects transported by helicopter without replacement.

We need to find the probability that none of them left the treatment center against medical advice.

So, it must belong to 41017 group of patients.

So, Probability will be

$\mathbf{\frac{^{41017}C_{60}}{^{41315}C_{60}}\\\\\approx 0.64}$