Question

In a submarine equipped with sonar, the time delay between the generation of a pulse and its echo afer refection from an enemy submarine is observed to be 80 s. If the speed of sound in water 1460 ms⁻¹. What is the distance of enemy submarine?

Answer 1

in a submarine equipped with sonar , the speed of sound under water , distance of enemy submarine and time is related as v = 2d/t
Here v is the speed of sound in water , d is the distance of enemy submarine and t is the time.

Given,
v = 1460 m/s , t = 80 sec
∴ d = vt/2 = 1460 × 80/2 = 1460 × 40 = 58400 m = 58.4 km

Hence , distance of enemy submarine = 58.4 km

Answer 2

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Let the distance between the ship and the enemy submarine be ‘S’.

Speed of sound in water = 1450 m/s

Time lag between transmission and reception of Sonar waves = 77 s

In this time lag, sound waves travel a distance which is twice the distance between the ship and the submarine (2S).

Time taken for the sound to reach the submarine

=1/2 × 77 =38.5 s

Distance between the ship and the submarine (S) = 1450 × 38.5 = 55825 m = 55.8 km

I hope, this will help you

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