Math, asked by manjunathgowda657, 9 months ago

In a survey of 100 students of a college it was found that 49 liked watching football, 53 lik
watching hockey and 62 liked watching basket ball. 27 liked watching football and hocke
both, 29 liked watching basket ball and hockey both, 28 liked watching football and baskı
ball both. 5 liked watching none.
Based on the above information
How many students like watching only one of the three given games ?
(a) 41
(b) 21
(c) 20
(d) 12​

Answers

Answered by sidk57
11

Answer:

Step-by-step explanation:answer will be 41 students see image attached

Attachments:
Answered by amitnrw
4

41 students like watching only one of the three given games

Step-by-step explanation:

Total Students = 100

Liked Watching FootBall  F = 49

Liked Watching Hockey  H = 53

Liked Watching BasketBall B = 62

FootBall & Hockey  F ∩ H  = 27

BasketBall & Hockey  B ∩ H  = 29

Basketball & Football = B ∩ F = 28

All three  B ∩ H ∩ F = ?

None =  5

Total = F + H + B - F ∩ H - B ∩ H  - B ∩ F +  B ∩ H ∩ F + None

=> 100 = 49 + 53 + 62 - 27 - 29 - 28 +  B ∩ H ∩ F + 5

=>B ∩ H ∩ F = 15

Only Fottball =  F - B ∩ F - F ∩ H + B ∩ H ∩ F = 49  - 28 - 27 + 15=  9

Only Basketball = B - B ∩ F - B ∩ H + B ∩ H ∩ F = 62  - 28 - 29 + 15=  20

Only Hockey =  H - B ∩ H - F ∩ H + B ∩ H ∩ F = 53  - 29 - 27 + 15=  12

students like watching only one of the three given games = 9 + 20 + 12

= 41

41 students like watching only one of the three given games

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