Question

In a survey of 60 people it was found that 25 people read newspaper H, 26

read newspaper T, 26 read newspaper I, 9 read both H and I, 11 read both H and

T, 8 read both T and I, 3 read all three newspaper. Find the number of people:

i) Who read at least one of the newspapers.

ii) Who read exactly one newspaper.

iii) Who read only newspaper H.​

Answer 1

Answer:

sorry

Step-by-step explanation:

sorry i am really sorry

Answer 2

Answer:

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Step-by-step explanation:

Let A be the set of people who read newspaper H.

Let B be the set of people who read newspaper T.

Let C be the set of people who read newspaper I.

Given n(A)=25,n(B)=26, and n(C)=26

n(A∩C)=9,n(A∩B)=11, and (B∩C)=8

n(A∩B∩C)=3

Let U be the set of people who took part in the survey.

(i) n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(C∩A)+n(A∩B∩C)

=25+26+26−11−8−9+3

=52

Hence, 52 people read at least one of the newspaper.

(ii) Let a be the number of people who read newspapers H and T only.

Let b denote the number of people who read newspapers I and H only.

Let c denote the number of people who read newspaper T and I only.

Let d denote the number of people who read all three newspaper.

Accordingly, d=n(A∩B∩C)=3

Now, n(A∩B)=a+d

n(B∩C)=c+d

n(C∩A)=b+d

∴a+d+c+d+b+d=11+8+9=28

⇒a+b+c+d=28−2d=28−6=22

Hence, (52−22)=30 people read exactly one newspaper.