Question

in a swimming pool measuring 90 m*40 m,150 men take a dip.If the average displacement of water by a man is 8 m^3,then rise in water level is:
(a)27.33 cm
(b)30 cm
(c)31.33 cm
(d)33.33 cm

Answer 1

Answer:

ans.  (d)

Step-by-step explanation:

rise in water level is  1200/3600 = 1/3 m = 33.33cm.

choose ans.  (d)

Answer 2

The water level rises 0.33 m

Step-by-step explanation:

Given,

l = 90 m

b = 40 m

Total volume displayed by 8 men, = $150\times 8$$m^3$

However,

$Volume = l\times b\times h$

Where, h = height of the water level rises

Then ,

$150\times 8 = 90\times 40\times h$

or,

$h = \frac{150\times 8}{90\times 40}$

h = 0.333 m

Option (b).The water level rises 0.33 m