Question

in a system in which unit of mass, length of time is double.what is the value of 1 erg in that system.​

Answer 1

Explanation:

We know that,

Unit formula of power

power(p)=

time

work

p=

time

force×displacment

p=force×velocity

Now, dimension formula of power

=[MLT

−2

][LT

−1

]

If mass, length and time is doubled

Then,

p=[MLT

−2

][LT

−1

]

p=[ML

2

T

−3

]

p=[2M(2L)

2

(2T)

−3

]

p=[ML

2

T

−3 ]

Hence, the unit of power is p=[ML 2 T −3 ]

No change will occur in the unit.