Physics, asked by Anonymous, 8 months ago

In a system of two particles of 0.1 kg and 0.2 kg . The particle of .1 kg is at rest ,whereas other particle moves with acceleration a . the magnitude of acc. of centre of mass of system of two particle system is :​

Answers

Answered by subratac083
2

Answer:

2a÷3

Explanation:

a=m1a1+m2a2÷(m1+m2)

.2a÷(.2+.1)

.2a÷.3a=ax

ax=2a÷3

acc.=2a÷3

Answered by Anonymous
3

accleration of center, of mass acm =

m1 a2 +m2 a2/m1 m2

= g+2g / 1+2

= 3g/3

= g

...............

may this help you

good afternoon have a great day ahed....

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