In a system of two particles of 0.1 kg and 0.2 kg . The particle of .1 kg is at rest ,whereas other particle moves with acceleration a . the magnitude of acc. of centre of mass of system of two particle system is :
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Answered by
2
Answer:
2a÷3
Explanation:
a=m1a1+m2a2÷(m1+m2)
.2a÷(.2+.1)
.2a÷.3a=ax
ax=2a÷3
acc.=2a÷3
Answered by
3
accleration of center, of mass acm =
m1 a2 +m2 a2/m1 m2
= g+2g / 1+2
= 3g/3
= g
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may this help you
good afternoon have a great day ahed....
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