Question

in a test minimum passing percentage for girls and boys is 30% and 45% respectively a boy scored 280 marks and failed by 80 marks how many more marks did a girl require to pass in the test if she scored a 108 marks​

Answer 1

Let total no be x

45%of x= 280 + 80=360

X × 45/ 100=360

X= 800

Percentage required to pass girl = 30%

800×30/100 = 240

Ans: 240 marks

Answer 2

Answer:

132

Step-by-step explanation:

Given :

In a test minimum passing percentage for girls & boys are 30% & 45% respectively. A boy scored  280 and need 80 more marks to pass the examination. A girl scored 108 marks,.

To Find :

The difference between the original mark secured by the girl and the marks to be secured by the girl to pass the examination,.

Solution :

Let the total marks be x,

Statement 1 :

A boy scored  280 and need 80 more marks to pass the examination.

&

Minimum passing percentage for boys is 45%

Hence,

$280 + 80 = \frac{45}{100} x$

⇒ $360 = \frac{45}{100} x$

⇒ $x = 360 \times \frac{100}{45} = 800$

⇒ x = 800

_

The passing percentage for girls is 30%,.

Hence, the mark to be secured by the girls to pass the examination is $\frac{30}{100} x$

Hence,

$\frac{30}{100} x = \frac{30}{100} \times 800 = 8 \times 30 = 240$

The total marks to be scored by the girls is 240,.

_

The girl required 240 marks to pass the examination,

But, she scored 108 ,.

Hence , she needed :

240 - 108 = 132

∴ She needed 132 more marks to pass the examination,.