in a test, the students of 10th class scored marks are 42,46,32,46,40,25, then what is the average of the given data
Answers
Answer:
Hello,
Solution:
1) Mean = sum of all observation/ Total number of observation
Total Students = 15
Value of observation= 41, 39, 48, 52, 46, 62, 54, 40, 96, 52, 98, 40, 42, 52, 60
Mean =
\begin{lgathered}\frac{41 + 39 + 48 +52 + 46 + 62 + 54 + 40 + 96 + 52 + 98 + 40 + 42 + 52 + 60}{15} \\ \\ = \frac{822}{15} \\ \\ = 54.8\end{lgathered}
15
41+39+48+52+46+62+54+40+96+52+98+40+42+52+60
=
15
822
=54.8
Median:
1) Arrange data in ascending order
39,40,40,41,42,46,48,52,52,52,54,60,62,96,98
2) Total numbers of observation= 15
Odd: (n+1)/2
=(15+1)/2 = 8 th element is median
Median = 52
Mode:
1) Arrange data in ascending order
39,40,40,41,42,46,48,52,52,52,54,60,62,96,98
2) Count the frequency of each observation,the observation having most frequency is the mode
So, 52 appears 3 time,maximum time
Mode = 52
Hope it helps you.
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