Question

in a three digit number, the tens digit is equal to the sum of the hundreds digit and the units digit. The hundreds digit of his number is three more than the units digti. if the digits are digits are reversed. the new numbers is 11 less than the original number/ What is the original number?

Answer 1

Answer:

dfsdfsddddddddddsdssdfsdfsdfsdsdfsdfsssssssssssssssssssssssss

Step-by-step explanation:

Answer 2

Given,

The tens digit is equal to the sum of the hundreds digit and the units digit.

The hundreds digit of the number is three more than the units digit.

If the digits are digits are reversed, the new numbers is 11 less than the original number.

To find,

The original number

Solution:

Let us take the unit digit number be x, the tenth digit number be y and the hundredth digit number be z.

So the number will be,

• 100z+10y+x...(1)

Given, the tens digit is equal to the sum of the hundreds digit and the units digit.

Hence,

• y = z+x... (2)

Also, the hundreds digit of the number is three more than the units digit.

• z = x+3...(3)

Substitute (3) in (2)

• y = x+3+x
• y = 2x+3...(4)

If the digits are digits are reversed, the new numbers is 11 less than the original number. The new number be 100x+10y+z.

• 100z+10y+x = 100x+10y+z-11...(5)

Substitute (4) in (5)

• 100z+10(2x+3)+x = 100x+10(2x+3)+z-11
• 100z+x = 100x+z-11
• 99z = 99x-11
• 9(x-3) = 9x-1
• 9x-3 ≠ 9x-1

Hence, the given question is incorrect.

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