Question

in a throw of two dice,find the probability of getting a sum of 10

Answer 1

Total outcomes are n(s) 36
Sum equal to 10 are n(a) 3={4,6 5,5 6,4}
Therefore probability of an event is n(a) /n(s) 3/36=1/12

Answer 2

total possible outcomes = 6x6 = 36 
favourable outcomes = (4,6) ( 6,4) ( 5,5) = 3 
p roblablity = f outcomes / total possible outcomes 
p = 3 / 36 
p = 1/12