Question

In a throw of two dice the probability of obtaining getting distinct number is
:Answer please
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Answer 1

Answer:

hey mate here is your answer

5/6

Answer 2

answer:

Total number of out comes:

$n(t) = 6^{2} \\ = 36$

probability of getting same number (1,1), (2,2), (3,3), (4,4), (5,5) and (6,6) is given as,

$n(p) = \frac{6}{36} \\ = \frac{1}{6}$

therefore, the probability of getting all distinct number is,

$n(e) = 1 - n(p) \\ = 1 - \frac{1}{6} \\ = \frac{5}{6}$