in a throw of two dice what is the probability that the product of two numbers is less than 6
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0
what we have to find
bushraharoon:
it's given in the question itself i guess you haven't read the question properly.
Let the event A be the product of two number be less then 6
A=(1,2 1,3 1,4 1,5 2,1 2,2 )
P(A)= 6
P (a)= nA÷nS = 6÷12= 2
P(A)=2
Answered by
1
Possible outcomes:
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4)(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5,(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)
total = 36
No of favourable outcomes :10
= (1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,2),(3,1),(4,1),(5,1)
probability : 10/36
=5/18
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4)(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5,(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)
total = 36
No of favourable outcomes :10
= (1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,2),(3,1),(4,1),(5,1)
probability : 10/36
=5/18
thanks.
welcome
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