in a titration, 60 mL of Phosphoric acid (H3PO4) completely nutralizes 750 mL of sodium carbonate solution containing 3.18 gm of NA2CO3 in one litre solution. calculate the molarity of phosphoric acid.
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2H3PO4 (aq) + 3Na2CO3 (aq) ------> 2Na3PO4 (aq) + 3CO2(g) + 3H2O(i)
Na2CO3 = 23X2 + 12 + 16X3 = 106
Molarity of Na2CO3 = 3.18/106 = 0.03M
from the equation
(Ma x Va)/(Mb x Vb) = 2/3
(Ma x 60)/(0.03 x 750) = 2/3
Ma x 60 = 2/3 x 0.03 x 750 = 15
Ma = 15/60 = 0.25 M
Molarity of phosphoric acid = 0.25M
Na2CO3 = 23X2 + 12 + 16X3 = 106
Molarity of Na2CO3 = 3.18/106 = 0.03M
from the equation
(Ma x Va)/(Mb x Vb) = 2/3
(Ma x 60)/(0.03 x 750) = 2/3
Ma x 60 = 2/3 x 0.03 x 750 = 15
Ma = 15/60 = 0.25 M
Molarity of phosphoric acid = 0.25M
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