Question

In a transaction, the profit percentage is 80% of the cost. If the cost further increases by 20% but the selling price remains the same, how much is the decrease in profit percentage?​

Answer 1

Step-by-step explanation:

Let the C.P = ₹100

profit is 170% of Cost Price

> profit = 170/100* (100)= 170

s.p = c.p + profit = 100+170=270

now

Cost Price increases bt 20 % but the Sell Price remains same

New C.p = 120/100*(100) = 120

s.p = 270 (same)

Profit = s.p-c.p = 270-120 = 150

Profit % = profit/c.p *100

= 150/120 * 100 = 5/4 *100 = 125 %

Answer 2

Answer:

30% is the decrease in the profit percentage.

Step-by-step explanation:

To find:-

The decrease in the profit percentage.

Let the cost price be Rs.100.

According to the question,

The profit percentage is 80% of the cost, i.e.,

Profit = 80% of the cost price

         = 80% × 100

         = $\frac{80}{100}\times 100$

         = Rs.80

As we know,

Selling price = Cost price + Profit

                     = 100 + 80

                     = Rs.180

Now,

The cost price increases by 20% and the selling price remains the same.

The new cost price = 100 + 20% of 100

                                 = 100 + $\frac{20}{100}\times100$

                                 = 100 + 20

                                 = Rs.120

Thus,

The new profit = Selling price - Cost price

                         = 180 - 120

                         = Rs.60

The profit percentage = (New profit)/New cost price × 100

                                      = $\frac{60}{120}\times100$

                                      = 50%

The decrease in the profit percentage = 80 - 50

                                                                  = 30%

Therefore, the decrease in the profit percentage is 30%.

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