Question

In a transformers, number of turns in primary
coil are 140 and that in secondary coil are 280. If
current in primary coil is 4A, then that in
secondary coil is
(a) 4 A (b) 2 A
(c) 6 A (d) 10 A

Answer 1

Answer:

In a transformer, the number of turnsin the primary coil is 140 and that in the secondary coil is 280. If thecurrent in the primary coil is 4A, thenthat in the secondary coil is.

N1 I1

------ = ---------

N2 I2

I2= N1*I1

----------

N2

= 140*4

-----------

280

= 2A.

Answer 2

Answer:

In a transformer, the number of turnsin the primary coil is 140 and that in the secondary coil is 280. If thecurrent in the primary coil is 4A, thenthat in the secondary coil is.

N1/N2 = I1/I2

I2 = N1*I1 / N2

= 140*4/ 280

= 2 Ampere