Question

In a transistor amplifier beta= 62 r=5000ohm and internal resistance of transistor is 500ohm its power amplification is

Answer 1

Hey mate,

● Answer-
Power amplification = 620.

● Explaination-
# Given-
β = 62
Ro = 5000 ohm
Ri = 500 ohm

# Solution-
Power amplification is given by-
Power ampl. = β (Ro/Ri)
Power ampl. = 62 (5000/500)
Power ampl. = 620

Therefore, power amplification of the transitor is given by 620.

Hope this helps you.
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