The product of 3 consecutive integer is divisible by 6
Answers
Answered by
1
hi
aim :to show that The product of 3 consecutive integer is divisible by 6
let the integegers be n
then other 2
n +1 : n +2
now,
let n be 2
then 2 * [2 +1] *[ 2*2]
=>2 * 3*4
=> 24
now 24 / 6
= 4
hence The product of 3 consecutive integer is divisible by 6
hope it helps u
:)
aim :to show that The product of 3 consecutive integer is divisible by 6
let the integegers be n
then other 2
n +1 : n +2
now,
let n be 2
then 2 * [2 +1] *[ 2*2]
=>2 * 3*4
=> 24
now 24 / 6
= 4
hence The product of 3 consecutive integer is divisible by 6
hope it helps u
:)
Answered by
0
let the first consecutive integer = x
then the second consecutive integer = x +1
then the third consecutive integer = x +2
ATQ
x + x+1 +x+2 =6
3x+3 =6
3x =6-3
3x = 3
x = 3/3
x = 1
so the first consecutive integer =x
=1
second consecutive integer =x+1 = 1+1 =2
third consecutive integer = x+2. = 1+2 3
so the integers are 1 2 3
then the second consecutive integer = x +1
then the third consecutive integer = x +2
ATQ
x + x+1 +x+2 =6
3x+3 =6
3x =6-3
3x = 3
x = 3/3
x = 1
so the first consecutive integer =x
=1
second consecutive integer =x+1 = 1+1 =2
third consecutive integer = x+2. = 1+2 3
so the integers are 1 2 3
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