Physics, asked by Vency2304, 7 months ago

In a transistor, IC = 100 mA and IE = 100.2 mA. The value of β is

Answers

Answered by azaziabdullah207207
29

Answer:

Explanation:

In that case the current gain is β = Ic/Ib = Ic / (Ie - Ic) = 100 / (100.2 - 100) = 100/0.2 = 500.

Answered by steffiaspinno
0

99

In a transistor,

IB- base current

IE- emitter current

IC- collector current

β- gain factor of transistor

The formula to find the gain factor of transistor is

β = IC/IB

In this problem, the values IC = 100 mA and IE = 100.2 mA are given.

β = alpha/1-alpha

alpha = IC/IE = 100/100.2 = 0.99

β = 0.99/1-0.99 = 0.99/0.01 = 99

Hence, the value of β is 99.

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