Math, asked by amolkatiyar07, 5 months ago

In a trapezium ABCD, AB//CD, AD=BC,If angle A is 70 degree, then angle B, C,and D in degree is​

Answers

Answered by akio99
1
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Answered by Anonymous
24

In trapezium ABCD, AB∥CD, AD=BC

Draw a perpendicular from A on CD to meet CD at M and a perendicular from B on CD to meet at N.

Now, in △ADM and △BNC

∠AMD=∠BNC (Each 90 o )

AM=BN (distance between parallel lines)

AD=BC (Given)

Thus, △ADM≅△BCN (SAS rule)

Hence, ∠D=∠C=76 ∘

(by CPCT)

Answer by @Neelraj

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