In a trapezium ABCD, AB//CD, AD=BC,If angle A is 70 degree, then angle B, C,and D in degree is
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In trapezium ABCD, AB∥CD, AD=BC
Draw a perpendicular from A on CD to meet CD at M and a perendicular from B on CD to meet at N.
Now, in △ADM and △BNC
∠AMD=∠BNC (Each 90 o )
AM=BN (distance between parallel lines)
AD=BC (Given)
Thus, △ADM≅△BCN (SAS rule)
Hence, ∠D=∠C=76 ∘
(by CPCT)
Answer by @Neelraj
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