Question

In a trapezium ABCD, AB is parallel to DC, AB = 4.5 cm, BC = 5 cm, CD= 7.5and AD = 6 cm. the point X lies on CD such that BX is parallel to AD . find <BCX and the length of BD​
please use sine , cos and tan rule to solve this answer

Answer 1

Answer:

386895

Step-by-step explanation:

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Answer 2

Answer:

HELLO! ☺✔️

Its given that DE is parallel to BC and AD=BD/2.

That means Point D is on the line AB and its divided line in 1:2 from point A. that is AD=x then BD =2x.

then, AB=3x.

Now look for two similar triangles (ABC) And tringal (ADE).

Apply similar triangle properties.

(AD/AB)=(DE/BC)

we have BC=4.5 c.m

Hence,

DE=(AD/AB)*BC

DE=(x/(3*x))*4.5

DE=(1/3)*4.5

DE=1.5 c.m

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