In a Trapezium ABCD ab parallel to CD and ADparallel to BC if P is a point of intersection of diagonals 9 AC and BD prove that Pintu PC equal to PB into PD
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Secondary SchoolMath5 points
ABCD is a trapezium in which AB//DC.If P is the point of intersection of diagonals AC and BD such that area of triangle APB =32 cm^2 and area of triangle DPC =50 cm^2, then find the area of trapezium ABCD
Ask for details Follow Report by Sinha11102.10.2018
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Me · Beginner
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rrjack29 Genius
The area of Trapezium = 1/2(AB+CD).H
Let AB = 4x & CD = 5x (since you already found that sides are in 4:5)
Let the heights be h1 & h2 respectively.
Then H = h1 + h2
Area = 1/2 * (4x+5x)(h1+h2)
= 1/2 * 9x * h1 + 1/2 * 9x * h2
1/2 * 4x*h1 = 32
1/2 * 9x*h1 = 32 * 9/4 = 72
1/2 * 5x * h2 = 50
1/2 * 9x * h2 = 50 * 9/5 = 90
Area = 72 + 90 = 162
Secondary SchoolMath5 points
ABCD is a trapezium in which AB//DC.If P is the point of intersection of diagonals AC and BD such that area of triangle APB =32 cm^2 and area of triangle DPC =50 cm^2, then find the area of trapezium ABCD
Ask for details Follow Report by Sinha11102.10.2018
Answers
Me · Beginner
Know the answer? Add it here!

rrjack29 Genius
The area of Trapezium = 1/2(AB+CD).H
Let AB = 4x & CD = 5x (since you already found that sides are in 4:5)
Let the heights be h1 & h2 respectively.
Then H = h1 + h2
Area = 1/2 * (4x+5x)(h1+h2)
= 1/2 * 9x * h1 + 1/2 * 9x * h2
1/2 * 4x*h1 = 32
1/2 * 9x*h1 = 32 * 9/4 = 72
1/2 * 5x * h2 = 50
1/2 * 9x * h2 = 50 * 9/5 = 90
Area = 72 + 90 = 162
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